Okay - sorry I'm confused how does a 1:150 split of a 1ul injection of a 250ppm standard give you 10ng on column. I think my calculations must be off. We have always done 2ul of a 500ppm standard at a 1:50 split. Shouldn't this give us 20ng on column?
I was thinking the same thing. 250ng/ul / 150 = 1.667ng on column.
We currently use 50ppb BFB in our surrogate so when we purge 5ml of 50ppb and have a 50:1 split we are actually putting 5ng on column which passes easily.
250ng in 5ml sample / 50(split) = 5ng on column.
I use the auto find which is the old CLP method where it takes the center three scans averaged and subtracts one scan prior to the BFB peak. If this fails we then look at individual scans of the BFB peak or an average of the entire peak. The method doesn't state exactly how the spectra must be generated that I have seen.
Since Agilent systems actually scan from highest to lowest mass, you will notice a bias towards lower masses on the front of the peak and bias towards higher masses on the tail of the peak. This makes the average methods more representative of the actual balance of the system.